${{\boldsymbol \rho}_{{3}}{(1690)}}$ $\rightarrow$ 4 ${{\boldsymbol \pi}}$ INSPIRE search

$\Gamma($ ${{\mathit \rho}_{{3}}{(1690)}}$ $\rightarrow$ ${{\mathit \pi}}{{\mathit \pi}}$ $)/\Gamma($ ${{\mathit \rho}_{{3}}{(1690)}}$ $\rightarrow$ 4 ${{\mathit \pi}}$ $)$
$\Gamma_{4}/\Gamma_{1}$
M015R3