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${{\mathit K}^{*}{(1680)}}$
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${{\boldsymbol K}^{*}{(1680)}}$ $\rightarrow$ ${{\boldsymbol K}}{{\boldsymbol \phi}}$
${{\boldsymbol K}^{*}{(1680)}}$ $\rightarrow$ ${{\boldsymbol K}}{{\boldsymbol \phi}}$
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$\Gamma($ ${{\mathit K}^{*}{(1680)}}$ $\rightarrow$ ${{\mathit K}}{{\mathit \phi}}$ $)/\Gamma_{\text{total}}$
$\Gamma_{4}/\Gamma$
M095R00
