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${{\mathit f}_{{4}}{(2050)}}$
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${{\boldsymbol f}_{{4}}{(2050)}}$ $\rightarrow$ 4 ${{\boldsymbol \pi}^{0}}$
${{\boldsymbol f}_{{4}}{(2050)}}$ $\rightarrow$ 4 ${{\boldsymbol \pi}^{0}}$
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$\Gamma($ ${{\mathit f}_{{4}}{(2050)}}$ $\rightarrow$ 4 ${{\mathit \pi}^{0}}$ $)/\Gamma_{\text{total}}$
$\Gamma_{5}/\Gamma$
M016R4