${{\boldsymbol a}_{{1}}{(1640)}}$ $\rightarrow$ ${{\boldsymbol \omega}}{{\boldsymbol \pi}}{{\boldsymbol \pi}}$ INSPIRE search

$\Gamma($ ${{\mathit a}_{{1}}{(1640)}}$ $\rightarrow$ ${{\mathit \omega}}{{\mathit \pi}}{{\mathit \pi}}$ $)/\Gamma_{\text{total}}$
$\Gamma_{6}/\Gamma$
M161R3