${{\boldsymbol a}_{{1}}{(1640)}}$ $\rightarrow$ ${{\boldsymbol a}_{{1}}{(1260)}}{{\boldsymbol \eta}}$ INSPIRE search

$\Gamma($ ${{\mathit a}_{{1}}{(1640)}}$ $\rightarrow$ ${{\mathit a}_{{1}}{(1260)}}{{\mathit \eta}}$ $)/\Gamma_{\text{total}}$
$\Gamma_{8}/\Gamma$
M161R5