${{\boldsymbol \Lambda}_{{c}}{(2595)}^{+}}$ $I(J^P)$ = $0(1/2^{-})$
The ${{\mathit \Lambda}_{{c}}^{+}}{{\mathit \pi}^{+}}{{\mathit \pi}^{-}}$ mode is largely, and perhaps entirely, ${{\mathit \Sigma}_{{c}}}{{\mathit \pi}}$ , which is just at threshold; since the ${{\mathit \Sigma}_{{c}}}$ has $\mathit J{}^{P} = 1/2{}^{+}$, the $\mathit J{}^{P}$ here is almost certainly ${}^{}1/2{}^{-}$. This result is in accord with the theoretical expectation that this is the charm counterpart of the strange ${{\mathit \Lambda}{(1405)}}$.