${{\boldsymbol \Omega}_{{c}}^{0}}$ $I(J^P)$ = $0(1/2^{+})$
The quantum numbers have not been measured, but are simply assigned in accord with the quark model, in which the ${{\mathit \Omega}_{{c}}^{0}}$ is the ${\mathit {\mathit s}}$ ${\mathit {\mathit s}}$ ${\mathit {\mathit c}}$ ground state. No absolute branching fractions have been measured.